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50681457281113 is a prime number
BaseRepresentation
bin10111000011000001100100…
…10000100000100001011001
320122110002200220020221111121
423201200302100200201121
523120331111030443423
6255442423503525241
713450420520634541
oct1341406220404131
9218402626227447
1050681457281113
111516a98141061a
1258264a55b9821
13223831939b2b9
14c72dd1daa321
155cd51ada845d
hex2e1832420859

50681457281113 has 2 divisors, whose sum is σ = 50681457281114. Its totient is φ = 50681457281112.

The previous prime is 50681457280939. The next prime is 50681457281123. The reversal of 50681457281113 is 31118275418605.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46970297766144 + 3711159514969 = 6853488^2 + 1926437^2 .

It is a cyclic number.

It is not a de Polignac number, because 50681457281113 - 213 = 50681457272921 is a prime.

It is a super-2 number, since 2×506814572811132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (50681457281123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25340728640556 + 25340728640557.

It is an arithmetic number, because the mean of its divisors is an integer number (25340728640557).

Almost surely, 250681457281113 is an apocalyptic number.

It is an amenable number.

50681457281113 is a deficient number, since it is larger than the sum of its proper divisors (1).

50681457281113 is an equidigital number, since it uses as much as digits as its factorization.

50681457281113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1612800, while the sum is 52.

The spelling of 50681457281113 in words is "fifty trillion, six hundred eighty-one billion, four hundred fifty-seven million, two hundred eighty-one thousand, one hundred thirteen".