Base | Representation |
---|---|
bin | 101111001110011000… |
… | …010101001111001001 |
3 | 11211212212101212000211 |
4 | 233032120111033021 |
5 | 1312322011001233 |
6 | 35143341401121 |
7 | 3443366311144 |
oct | 571630251711 |
9 | 154785355024 |
10 | 50707125193 |
11 | 1a56093973a |
12 | 99b18691a1 |
13 | 4a214052ba |
14 | 265060105b |
15 | 14bb9c35cd |
hex | bce6153c9 |
50707125193 has 2 divisors, whose sum is σ = 50707125194. Its totient is φ = 50707125192.
The previous prime is 50707125181. The next prime is 50707125229. The reversal of 50707125193 is 39152170705.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42883368889 + 7823756304 = 207083^2 + 88452^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50707125193 is a prime.
It is not a weakly prime, because it can be changed into another prime (50707125113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25353562596 + 25353562597.
It is an arithmetic number, because the mean of its divisors is an integer number (25353562597).
Almost surely, 250707125193 is an apocalyptic number.
It is an amenable number.
50707125193 is a deficient number, since it is larger than the sum of its proper divisors (1).
50707125193 is an equidigital number, since it uses as much as digits as its factorization.
50707125193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 66150, while the sum is 40.
Adding to 50707125193 its reverse (39152170705), we get a palindrome (89859295898).
The spelling of 50707125193 in words is "fifty billion, seven hundred seven million, one hundred twenty-five thousand, one hundred ninety-three".
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