Base | Representation |
---|---|
bin | 100100111010011111111… |
… | …0000101111111101100011 |
3 | 122222000101210022112010101 |
4 | 1021310333300233331203 |
5 | 1131110334041324142 |
6 | 14442411053043231 |
7 | 1032354141326341 |
oct | 111647760577543 |
9 | 18860353275111 |
10 | 5073426120547 |
11 | 168669a865714 |
12 | 69b320186517 |
13 | 2aa56427b985 |
14 | 1377ab408991 |
15 | 8be889e90b7 |
hex | 49d3fc2ff63 |
5073426120547 has 2 divisors, whose sum is σ = 5073426120548. Its totient is φ = 5073426120546.
The previous prime is 5073426120509. The next prime is 5073426120563. The reversal of 5073426120547 is 7450216243705.
5073426120547 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5073426120547 - 211 = 5073426118499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5073426120497 and 5073426120506.
It is not a weakly prime, because it can be changed into another prime (5073426120577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2536713060273 + 2536713060274.
It is an arithmetic number, because the mean of its divisors is an integer number (2536713060274).
Almost surely, 25073426120547 is an apocalyptic number.
5073426120547 is a deficient number, since it is larger than the sum of its proper divisors (1).
5073426120547 is an equidigital number, since it uses as much as digits as its factorization.
5073426120547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1411200, while the sum is 46.
The spelling of 5073426120547 in words is "five trillion, seventy-three billion, four hundred twenty-six million, one hundred twenty thousand, five hundred forty-seven".
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