Base | Representation |
---|---|
bin | 100100111101010100011… |
… | …1001111100001101000011 |
3 | 122222121001001100211012121 |
4 | 1021322220321330031003 |
5 | 1131210241141324323 |
6 | 14445252214105111 |
7 | 1032660243002053 |
oct | 111725071741503 |
9 | 18877031324177 |
10 | 5079485104963 |
11 | 1689219a13355 |
12 | 6a053134b197 |
13 | 2aacbb62a359 |
14 | 137bc3dad563 |
15 | 8c1e08d3a5d |
hex | 49ea8e7c343 |
5079485104963 has 2 divisors, whose sum is σ = 5079485104964. Its totient is φ = 5079485104962.
The previous prime is 5079485104957. The next prime is 5079485105053. The reversal of 5079485104963 is 3694015849705.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5079485104963 - 221 = 5079483007811 is a prime.
It is not a weakly prime, because it can be changed into another prime (5079485104163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2539742552481 + 2539742552482.
It is an arithmetic number, because the mean of its divisors is an integer number (2539742552482).
Almost surely, 25079485104963 is an apocalyptic number.
5079485104963 is a deficient number, since it is larger than the sum of its proper divisors (1).
5079485104963 is an equidigital number, since it uses as much as digits as its factorization.
5079485104963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32659200, while the sum is 61.
The spelling of 5079485104963 in words is "five trillion, seventy-nine billion, four hundred eighty-five million, one hundred four thousand, nine hundred sixty-three".
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