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509534311849 is a prime number
BaseRepresentation
bin1110110101000101001…
…11001001010110101001
31210201012022200221022121
413122202213021112221
531322011240434344
61030024332351241
751545510122033
oct7324247112651
91721168627277
10509534311849
11187101921072
1282902015521
1339083507914
141a9395a2c53
15d3c2ba4684
hex76a29c95a9

509534311849 has 2 divisors, whose sum is σ = 509534311850. Its totient is φ = 509534311848.

The previous prime is 509534311817. The next prime is 509534311907. The reversal of 509534311849 is 948113435905.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 289155703824 + 220378608025 = 537732^2 + 469445^2 .

It is a cyclic number.

It is not a de Polignac number, because 509534311849 - 25 = 509534311817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 509534311796 and 509534311805.

It is not a weakly prime, because it can be changed into another prime (509534311249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 254767155924 + 254767155925.

It is an arithmetic number, because the mean of its divisors is an integer number (254767155925).

Almost surely, 2509534311849 is an apocalyptic number.

It is an amenable number.

509534311849 is a deficient number, since it is larger than the sum of its proper divisors (1).

509534311849 is an equidigital number, since it uses as much as digits as its factorization.

509534311849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2332800, while the sum is 52.

The spelling of 509534311849 in words is "five hundred nine billion, five hundred thirty-four million, three hundred eleven thousand, eight hundred forty-nine".