Base | Representation |
---|---|
bin | 100101000101001101001… |
… | …0110011111110100101001 |
3 | 200001012202022212100210211 |
4 | 1022022122112133310221 |
5 | 1131444432211124313 |
6 | 14501132520541121 |
7 | 1034130026024434 |
oct | 112123226376451 |
9 | 20035668770724 |
10 | 5096420801833 |
11 | 169541a752049 |
12 | 6a38790217a1 |
13 | 2ac78a1c7c6a |
14 | 13894d31081b |
15 | 8c882607e3d |
hex | 4a29a59fd29 |
5096420801833 has 2 divisors, whose sum is σ = 5096420801834. Its totient is φ = 5096420801832.
The previous prime is 5096420801807. The next prime is 5096420802037. The reversal of 5096420801833 is 3381080246905.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4003168627264 + 1093252174569 = 2000792^2 + 1045587^2 .
It is a cyclic number.
It is not a de Polignac number, because 5096420801833 - 29 = 5096420801321 is a prime.
It is a super-3 number, since 3×50964208018333 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5096420801803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2548210400916 + 2548210400917.
It is an arithmetic number, because the mean of its divisors is an integer number (2548210400917).
Almost surely, 25096420801833 is an apocalyptic number.
It is an amenable number.
5096420801833 is a deficient number, since it is larger than the sum of its proper divisors (1).
5096420801833 is an equidigital number, since it uses as much as digits as its factorization.
5096420801833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 49.
The spelling of 5096420801833 in words is "five trillion, ninety-six billion, four hundred twenty million, eight hundred one thousand, eight hundred thirty-three".
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