Base | Representation |
---|---|
bin | 1100001001111… |
… | …0011000110011 |
3 | 10112221001222002 |
4 | 3002132120303 |
5 | 101022333103 |
6 | 5020404215 |
7 | 1156216625 |
oct | 302363063 |
9 | 115831862 |
10 | 50980403 |
11 | 26860371 |
12 | 150a666b |
13 | a73c726 |
14 | 6ab0c15 |
15 | 4720488 |
hex | 309e633 |
50980403 has 2 divisors, whose sum is σ = 50980404. Its totient is φ = 50980402.
The previous prime is 50980393. The next prime is 50980421. The reversal of 50980403 is 30408905.
50980403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50980403 - 28 = 50980147 is a prime.
It is not a weakly prime, because it can be changed into another prime (50980493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25490201 + 25490202.
It is an arithmetic number, because the mean of its divisors is an integer number (25490202).
Almost surely, 250980403 is an apocalyptic number.
50980403 is a deficient number, since it is larger than the sum of its proper divisors (1).
50980403 is an equidigital number, since it uses as much as digits as its factorization.
50980403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
The square root of 50980403 is about 7140.0562322716. The cubic root of 50980403 is about 370.7954714308.
The spelling of 50980403 in words is "fifty million, nine hundred eighty thousand, four hundred three".
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