Base | Representation |
---|---|
bin | 100101000110111001010… |
… | …1110101001010000110001 |
3 | 200001120010022202002001201 |
4 | 1022031302232221100301 |
5 | 1132024401024314414 |
6 | 14502533040531201 |
7 | 1034316006214462 |
oct | 112156256512061 |
9 | 20046108662051 |
10 | 5100051010609 |
11 | 1696a12923695 |
12 | 6a4510920b01 |
13 | 2acc183240a9 |
14 | 138bb54c4d69 |
15 | 8c9e6185574 |
hex | 4a372ba9431 |
5100051010609 has 2 divisors, whose sum is σ = 5100051010610. Its totient is φ = 5100051010608.
The previous prime is 5100051010589. The next prime is 5100051010631. The reversal of 5100051010609 is 9060101500015.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3288999873600 + 1811051137009 = 1813560^2 + 1345753^2 .
It is a cyclic number.
It is not a de Polignac number, because 5100051010609 - 25 = 5100051010577 is a prime.
It is a super-3 number, since 3×51000510106093 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5100051010669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550025505304 + 2550025505305.
It is an arithmetic number, because the mean of its divisors is an integer number (2550025505305).
Almost surely, 25100051010609 is an apocalyptic number.
It is an amenable number.
5100051010609 is a deficient number, since it is larger than the sum of its proper divisors (1).
5100051010609 is an equidigital number, since it uses as much as digits as its factorization.
5100051010609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 28.
The spelling of 5100051010609 in words is "five trillion, one hundred billion, fifty-one million, ten thousand, six hundred nine".
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