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5100340121 is a prime number
BaseRepresentation
bin1001100000000000…
…10000001110011001
3111011110012010022222
410300000100032121
540421141340441
62202033553425
7240251114162
oct46000201631
914143163288
105100340121
112188011028
12ba4115875
13633891146
14365540769
151ecb76d4b
hex130010399

5100340121 has 2 divisors, whose sum is σ = 5100340122. Its totient is φ = 5100340120.

The previous prime is 5100340109. The next prime is 5100340139. The reversal of 5100340121 is 1210430015.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3960940096 + 1139400025 = 62936^2 + 33755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5100340121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5100340121.

It is not a weakly prime, because it can be changed into another prime (5100345121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2550170060 + 2550170061.

It is an arithmetic number, because the mean of its divisors is an integer number (2550170061).

Almost surely, 25100340121 is an apocalyptic number.

It is an amenable number.

5100340121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5100340121 is an equidigital number, since it uses as much as digits as its factorization.

5100340121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 5100340121 is about 71416.6655690393. The cubic root of 5100340121 is about 1721.3388846135.

Adding to 5100340121 its reverse (1210430015), we get a palindrome (6310770136).

The spelling of 5100340121 in words is "five billion, one hundred million, three hundred forty thousand, one hundred twenty-one".