Base | Representation |
---|---|
bin | 1110110110000010101… |
… | …10010101110010110011 |
3 | 1210202112021001121112122 |
4 | 13123001112111302303 |
5 | 31324040300000201 |
6 | 1030151433344455 |
7 | 51564341316134 |
oct | 7330126256263 |
9 | 1722467047478 |
10 | 510050000051 |
11 | 187346a23269 |
12 | 82a2686812b |
13 | 391362c3677 |
14 | 1a987c7dc8b |
15 | d4030bae1b |
hex | 76c1595cb3 |
510050000051 has 2 divisors, whose sum is σ = 510050000052. Its totient is φ = 510050000050.
The previous prime is 510050000027. The next prime is 510050000059. The reversal of 510050000051 is 150000050015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 510050000051 - 218 = 510049737907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 510049999984 and 510050000029.
It is not a weakly prime, because it can be changed into another prime (510050000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255025000025 + 255025000026.
It is an arithmetic number, because the mean of its divisors is an integer number (255025000026).
Almost surely, 2510050000051 is an apocalyptic number.
510050000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
510050000051 is an equidigital number, since it uses as much as digits as its factorization.
510050000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 125, while the sum is 17.
Adding to 510050000051 its reverse (150000050015), we get a palindrome (660050050066).
The spelling of 510050000051 in words is "five hundred ten billion, fifty million, fifty-one", and thus it is an aban number.
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