Base | Representation |
---|---|
bin | 101111100000011011… |
… | …110111110011111011 |
3 | 11212122222101200022201 |
4 | 233200123313303323 |
5 | 1313432032340011 |
6 | 35233402131031 |
7 | 3454035132625 |
oct | 574033676373 |
9 | 155588350281 |
10 | 51010043131 |
11 | 1a6a6926443 |
12 | 9a771b0a77 |
13 | 4a6c0b5298 |
14 | 267c933c15 |
15 | 14d83abcc1 |
hex | be06f7cfb |
51010043131 has 2 divisors, whose sum is σ = 51010043132. Its totient is φ = 51010043130.
The previous prime is 51010043089. The next prime is 51010043159. The reversal of 51010043131 is 13134001015.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51010043131 is a prime.
It is a super-2 number, since 2×510100431312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51010043099 and 51010043108.
It is not a weakly prime, because it can be changed into another prime (51010040131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25505021565 + 25505021566.
It is an arithmetic number, because the mean of its divisors is an integer number (25505021566).
Almost surely, 251010043131 is an apocalyptic number.
51010043131 is a deficient number, since it is larger than the sum of its proper divisors (1).
51010043131 is an equidigital number, since it uses as much as digits as its factorization.
51010043131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 19.
Adding to 51010043131 its reverse (13134001015), we get a palindrome (64144044146).
The spelling of 51010043131 in words is "fifty-one billion, ten million, forty-three thousand, one hundred thirty-one".
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