Base | Representation |
---|---|
bin | 10111001100101011100000… |
… | …11010010001110001000111 |
3 | 20200121211000111020210210101 |
4 | 23212111300122101301013 |
5 | 23141300024400330203 |
6 | 300255051333504531 |
7 | 13513403650601230 |
oct | 1346256032216107 |
9 | 220554014223711 |
10 | 51013212511303 |
11 | 15288644607309 |
12 | 587a8517a2147 |
13 | 22606aa108433 |
14 | c850a46d8087 |
15 | 5d6e8630441d |
hex | 2e6570691c47 |
51013212511303 has 32 divisors (see below), whose sum is σ = 61163939275776. Its totient is φ = 41598879049728.
The previous prime is 51013212511279. The next prime is 51013212511321. The reversal of 51013212511303 is 30311521231015.
It is not a de Polignac number, because 51013212511303 - 221 = 51013210414151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51013212511343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 146895076 + ... + 147241942.
It is an arithmetic number, because the mean of its divisors is an integer number (1911373102368).
Almost surely, 251013212511303 is an apocalyptic number.
51013212511303 is a deficient number, since it is larger than the sum of its proper divisors (10150726764473).
51013212511303 is a wasteful number, since it uses less digits than its factorization.
51013212511303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 351823.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 51013212511303 its reverse (30311521231015), we get a palindrome (81324733742318).
The spelling of 51013212511303 in words is "fifty-one trillion, thirteen billion, two hundred twelve million, five hundred eleven thousand, three hundred three".
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