51014113 has 2 divisors, whose sum is σ = 51014114. Its totient is φ = 51014112.

The previous prime is 51014099. The next prime is 51014123. The reversal of 51014113 is 31141015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50225569 + 788544 = 7087^2 + 888^2 .

It is a cyclic number.

It is not a de Polignac number, because 51014113 - 2⁵ = 51014081 is a prime.

It is not a weakly prime, because it can be changed into another prime (51014123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25507056 + 25507057.

It is an arithmetic number, because the mean of its divisors is an integer number (25507057).

Almost surely, 2^51014113 is an apocalyptic number.

It is an amenable number.

51014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51014113 is an equidigital number, since it uses as much as digits as its factorization.

51014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 51014113 is about 7142.4164678350. The cubic root of 51014113 is about 370.8771810066.

Adding to 51014113 its reverse (31141015), we get a palindrome (82155128).

The spelling of 51014113 in words is "fifty-one million, fourteen thousand, one hundred thirteen".