Base | Representation |
---|---|
bin | 100101000111101001000… |
… | …1000011010100000000101 |
3 | 200001201020212112111212121 |
4 | 1022033102020122200011 |
5 | 1132041140302221123 |
6 | 14503355535045541 |
7 | 1034403453055123 |
oct | 112172210324005 |
9 | 20051225474777 |
10 | 5101651601413 |
11 | 1697664369204 |
12 | 6a48989708b1 |
13 | 2b0111b05a43 |
14 | 138cc7cd0913 |
15 | 8ca8b94e75d |
hex | 4a3d221a805 |
5101651601413 has 4 divisors (see below), whose sum is σ = 5101690894720. Its totient is φ = 5101612308108.
The previous prime is 5101651601377. The next prime is 5101651601429. The reversal of 5101651601413 is 3141061561015.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5101651601413 - 217 = 5101651470341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5101651601443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19451253 + ... + 19711786.
It is an arithmetic number, because the mean of its divisors is an integer number (1275422723680).
Almost surely, 25101651601413 is an apocalyptic number.
It is an amenable number.
5101651601413 is a deficient number, since it is larger than the sum of its proper divisors (39293307).
5101651601413 is a wasteful number, since it uses less digits than its factorization.
5101651601413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39293306.
The product of its (nonzero) digits is 10800, while the sum is 34.
The spelling of 5101651601413 in words is "five trillion, one hundred one billion, six hundred fifty-one million, six hundred one thousand, four hundred thirteen".
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