Base | Representation |
---|---|
bin | 100101000111110111000… |
… | …0100011010110101101111 |
3 | 200001202110112111200210011 |
4 | 1022033232010122311233 |
5 | 1132043120300110041 |
6 | 14503514241154051 |
7 | 1034421204061546 |
oct | 112175604326557 |
9 | 20052415450704 |
10 | 5102120316271 |
11 | 16978849a7660 |
12 | 6a49a992b927 |
13 | 2b0187c55c04 |
14 | 138d3026115d |
15 | 8cab7b87e81 |
hex | 4a3ee11ad6f |
5102120316271 has 32 divisors (see below), whose sum is σ = 5819564881728. Its totient is φ = 4432001495040.
The previous prime is 5102120316263. The next prime is 5102120316311. The reversal of 5102120316271 is 1726130212015.
It is a cyclic number.
It is not a de Polignac number, because 5102120316271 - 23 = 5102120316263 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5102120316071) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6554155 + ... + 7291171.
It is an arithmetic number, because the mean of its divisors is an integer number (181861402554).
Almost surely, 25102120316271 is an apocalyptic number.
5102120316271 is a deficient number, since it is larger than the sum of its proper divisors (717444565457).
5102120316271 is a wasteful number, since it uses less digits than its factorization.
5102120316271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 737371.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 5102120316271 its reverse (1726130212015), we get a palindrome (6828250528286).
The spelling of 5102120316271 in words is "five trillion, one hundred two billion, one hundred twenty million, three hundred sixteen thousand, two hundred seventy-one".
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