Base | Representation |
---|---|
bin | 101111100001101100… |
… | …011100010101010001 |
3 | 11212201110010202001001 |
4 | 233201230130111101 |
5 | 1314002434223431 |
6 | 35235434542001 |
7 | 3454412511331 |
oct | 574154342521 |
9 | 155643122031 |
10 | 51031164241 |
11 | 1a707842002 |
12 | 9a82297901 |
13 | 4a7359ba95 |
14 | 26816710c1 |
15 | 14da17ee61 |
hex | be1b1c551 |
51031164241 has 2 divisors, whose sum is σ = 51031164242. Its totient is φ = 51031164240.
The previous prime is 51031164221. The next prime is 51031164253. The reversal of 51031164241 is 14246113015.
51031164241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28689584400 + 22341579841 = 169380^2 + 149471^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51031164241 is a prime.
It is not a weakly prime, because it can be changed into another prime (51031164221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25515582120 + 25515582121.
It is an arithmetic number, because the mean of its divisors is an integer number (25515582121).
Almost surely, 251031164241 is an apocalyptic number.
It is an amenable number.
51031164241 is a deficient number, since it is larger than the sum of its proper divisors (1).
51031164241 is an equidigital number, since it uses as much as digits as its factorization.
51031164241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 51031164241 its reverse (14246113015), we get a palindrome (65277277256).
The spelling of 51031164241 in words is "fifty-one billion, thirty-one million, one hundred sixty-four thousand, two hundred forty-one".
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