Base | Representation |
---|---|
bin | 101111100001101101… |
… | …000101111000000011 |
3 | 11212201110110101110100 |
4 | 233201231011320003 |
5 | 1314003010200103 |
6 | 35235442333443 |
7 | 3454414120410 |
oct | 574155057003 |
9 | 155643411410 |
10 | 51031334403 |
11 | 1a707948935 |
12 | 9a8235a283 |
13 | 4a7362b37a |
14 | 26816b7107 |
15 | 14da1b55a3 |
hex | be1b45e03 |
51031334403 has 24 divisors (see below), whose sum is σ = 84273696000. Its totient is φ = 29149861104.
The previous prime is 51031334381. The next prime is 51031334441. The reversal of 51031334403 is 30443313015.
51031334403 is a `hidden beast` number, since 5 + 1 + 0 + 313 + 344 + 0 + 3 = 666.
51031334403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 51031334403 - 212 = 51031330307 is a prime.
It is a super-2 number, since 2×510313344032 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51031334483) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19978 + ... + 320096.
It is an arithmetic number, because the mean of its divisors is an integer number (3511404000).
Almost surely, 251031334403 is an apocalyptic number.
51031334403 is a deficient number, since it is larger than the sum of its proper divisors (33242361597).
51031334403 is a wasteful number, since it uses less digits than its factorization.
51031334403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 302831 (or 302828 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
Adding to 51031334403 its reverse (30443313015), we get a palindrome (81474647418).
The spelling of 51031334403 in words is "fifty-one billion, thirty-one million, three hundred thirty-four thousand, four hundred three".
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