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5103251113 is a prime number
BaseRepresentation
bin1001100000010110…
…10110111010101001
3111011122200000110111
410300023112322221
540422413013423
62202220214321
7240314630062
oct46013267251
914148600414
105103251113
11218971a104
12ba509a3a1
1363437011c
14365a9b569
151ed04e60d
hex1302d6ea9

5103251113 has 2 divisors, whose sum is σ = 5103251114. Its totient is φ = 5103251112.

The previous prime is 5103251057. The next prime is 5103251123. The reversal of 5103251113 is 3111523015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3458380864 + 1644870249 = 58808^2 + 40557^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5103251113 is a prime.

It is not a weakly prime, because it can be changed into another prime (5103251123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2551625556 + 2551625557.

It is an arithmetic number, because the mean of its divisors is an integer number (2551625557).

Almost surely, 25103251113 is an apocalyptic number.

It is an amenable number.

5103251113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5103251113 is an equidigital number, since it uses as much as digits as its factorization.

5103251113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 22.

The square root of 5103251113 is about 71437.0430029127. The cubic root of 5103251113 is about 1721.6663040018. Note that the first 3 decimals are identical.

Adding to 5103251113 its reverse (3111523015), we get a palindrome (8214774128).

The spelling of 5103251113 in words is "five billion, one hundred three million, two hundred fifty-one thousand, one hundred thirteen".