Base | Representation |
---|---|
bin | 100101001000111011101… |
… | …0101000010001001111001 |
3 | 200001222102000200210001201 |
4 | 1022101313111002021321 |
5 | 1132112324311301301 |
6 | 14504534543014201 |
7 | 1034532235615234 |
oct | 112216725021171 |
9 | 20058360623051 |
10 | 5104423150201 |
11 | 16988568838a1 |
12 | 6a5330b9a361 |
13 | 2b0464080c3b |
14 | 1390ac02a41b |
15 | 8cb9ee19201 |
hex | 4a477542279 |
5104423150201 has 2 divisors, whose sum is σ = 5104423150202. Its totient is φ = 5104423150200.
The previous prime is 5104423150111. The next prime is 5104423150231. The reversal of 5104423150201 is 1020513244015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3992503515625 + 1111919634576 = 1998125^2 + 1054476^2 .
It is a cyclic number.
It is not a de Polignac number, because 5104423150201 - 29 = 5104423149689 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5104423150201.
It is not a weakly prime, because it can be changed into another prime (5104423150231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552211575100 + 2552211575101.
It is an arithmetic number, because the mean of its divisors is an integer number (2552211575101).
Almost surely, 25104423150201 is an apocalyptic number.
It is an amenable number.
5104423150201 is a deficient number, since it is larger than the sum of its proper divisors (1).
5104423150201 is an equidigital number, since it uses as much as digits as its factorization.
5104423150201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 5104423150201 its reverse (1020513244015), we get a palindrome (6124936394216).
The spelling of 5104423150201 in words is "five trillion, one hundred four billion, four hundred twenty-three million, one hundred fifty thousand, two hundred one".
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