Base | Representation |
---|---|
bin | 100101001001000010111… |
… | …1111010110100110000001 |
3 | 200002000001011112121001012 |
4 | 1022102011333112212001 |
5 | 1132113330243444433 |
6 | 14505015211050305 |
7 | 1034541313434014 |
oct | 112220577264601 |
9 | 20060034477035 |
10 | 5104669124993 |
11 | 1698972708349 |
12 | 6a539b440995 |
13 | 2b04a3014459 |
14 | 1390d297937b |
15 | 8cbb6805848 |
hex | 4a485fd6981 |
5104669124993 has 2 divisors, whose sum is σ = 5104669124994. Its totient is φ = 5104669124992.
The previous prime is 5104669124963. The next prime is 5104669124999. The reversal of 5104669124993 is 3994219664015.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4237224636304 + 867444488689 = 2058452^2 + 931367^2 .
It is a cyclic number.
It is not a de Polignac number, because 5104669124993 - 218 = 5104668862849 is a prime.
It is not a weakly prime, because it can be changed into another prime (5104669124999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552334562496 + 2552334562497.
It is an arithmetic number, because the mean of its divisors is an integer number (2552334562497).
Almost surely, 25104669124993 is an apocalyptic number.
It is an amenable number.
5104669124993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5104669124993 is an equidigital number, since it uses as much as digits as its factorization.
5104669124993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12597120, while the sum is 59.
The spelling of 5104669124993 in words is "five trillion, one hundred four billion, six hundred sixty-nine million, one hundred twenty-four thousand, nine hundred ninety-three".
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