Base | Representation |
---|---|
bin | 100101001001001101000… |
… | …0000110100111000101011 |
3 | 200002000220120122122002222 |
4 | 1022102122000310320223 |
5 | 1132120022243234111 |
6 | 14505112411144255 |
7 | 1034552533002233 |
oct | 112223200647053 |
9 | 20060816578088 |
10 | 5105005055531 |
11 | 16990252a2997 |
12 | 6a5473a4508b |
13 | 2b05277b2714 |
14 | 139125422cc3 |
15 | 8cbd60607db |
hex | 4a49a034e2b |
5105005055531 has 2 divisors, whose sum is σ = 5105005055532. Its totient is φ = 5105005055530.
The previous prime is 5105005055483. The next prime is 5105005055543. The reversal of 5105005055531 is 1355505005015.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5105005055531 - 222 = 5105000861227 is a prime.
It is a super-2 number, since 2×51050050555312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5105005055491 and 5105005055500.
It is not a weakly prime, because it can be changed into another prime (5105005055551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552502527765 + 2552502527766.
It is an arithmetic number, because the mean of its divisors is an integer number (2552502527766).
Almost surely, 25105005055531 is an apocalyptic number.
5105005055531 is a deficient number, since it is larger than the sum of its proper divisors (1).
5105005055531 is an equidigital number, since it uses as much as digits as its factorization.
5105005055531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46875, while the sum is 35.
The spelling of 5105005055531 in words is "five trillion, one hundred five billion, five million, fifty-five thousand, five hundred thirty-one".
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