Base | Representation |
---|---|
bin | 101111100011000011… |
… | …111111001010100011 |
3 | 11212210001022200102111 |
4 | 233203003333022203 |
5 | 1314024323112233 |
6 | 35242014500151 |
7 | 3455111542534 |
oct | 574303771243 |
9 | 155701280374 |
10 | 51054113443 |
11 | 1a719797093 |
12 | 9a89b04657 |
13 | 4a782756a8 |
14 | 268472668b |
15 | 14dc1b4acd |
hex | be30ff2a3 |
51054113443 has 2 divisors, whose sum is σ = 51054113444. Its totient is φ = 51054113442.
The previous prime is 51054113417. The next prime is 51054113471. The reversal of 51054113443 is 34431145015.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51054113443 - 221 = 51052016291 is a prime.
It is not a weakly prime, because it can be changed into another prime (51054183443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25527056721 + 25527056722.
It is an arithmetic number, because the mean of its divisors is an integer number (25527056722).
Almost surely, 251054113443 is an apocalyptic number.
51054113443 is a deficient number, since it is larger than the sum of its proper divisors (1).
51054113443 is an equidigital number, since it uses as much as digits as its factorization.
51054113443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 51054113443 its reverse (34431145015), we get a palindrome (85485258458).
The spelling of 51054113443 in words is "fifty-one billion, fifty-four million, one hundred thirteen thousand, four hundred forty-three".
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