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5105412113 is a prime number
BaseRepresentation
bin1001100000100111…
…00110100000010001
3111011210201210210112
410300103212200101
540423441141423
62202334411105
7240342200264
oct46023464021
914153653715
105105412113
11218a96575a
12ba5960a95
13634948919
143660a0cdb
151ed329a78
hex1304e6811

5105412113 has 2 divisors, whose sum is σ = 5105412114. Its totient is φ = 5105412112.

The previous prime is 5105412079. The next prime is 5105412133. The reversal of 5105412113 is 3112145015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3611048464 + 1494363649 = 60092^2 + 38657^2 .

It is a cyclic number.

It is not a de Polignac number, because 5105412113 - 210 = 5105411089 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (5105412133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552706056 + 2552706057.

It is an arithmetic number, because the mean of its divisors is an integer number (2552706057).

Almost surely, 25105412113 is an apocalyptic number.

It is an amenable number.

5105412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5105412113 is an equidigital number, since it uses as much as digits as its factorization.

5105412113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

The square root of 5105412113 is about 71452.1666081582. The cubic root of 5105412113 is about 1721.9092860908.

Adding to 5105412113 its reverse (3112145015), we get a palindrome (8217557128).

The spelling of 5105412113 in words is "five billion, one hundred five million, four hundred twelve thousand, one hundred thirteen".