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5105544402731 is a prime number
BaseRepresentation
bin100101001001011101000…
…1010010001011100101011
3200002002022011112022101012
41022102322022101130223
51132122123331341411
614505242115214135
71034602102245113
oct112227212213453
920062264468335
105105544402731
111699281794483
126a55a45a734b
132b05b2463186
14139176cdc043
158cc1859c18b
hex4a4ba29172b

5105544402731 has 2 divisors, whose sum is σ = 5105544402732. Its totient is φ = 5105544402730.

The previous prime is 5105544402713. The next prime is 5105544402817. The reversal of 5105544402731 is 1372044455015.

Together with previous prime (5105544402713) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5105544402731 - 210 = 5105544401707 is a prime.

It is a super-2 number, since 2×51055444027312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5105544422731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552772201365 + 2552772201366.

It is an arithmetic number, because the mean of its divisors is an integer number (2552772201366).

Almost surely, 25105544402731 is an apocalyptic number.

5105544402731 is a deficient number, since it is larger than the sum of its proper divisors (1).

5105544402731 is an equidigital number, since it uses as much as digits as its factorization.

5105544402731 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336000, while the sum is 41.

Adding to 5105544402731 its reverse (1372044455015), we get a palindrome (6477588857746).

The spelling of 5105544402731 in words is "five trillion, one hundred five billion, five hundred forty-four million, four hundred two thousand, seven hundred thirty-one".