Base | Representation |
---|---|
bin | 1110110110111111101… |
… | …00000010000101010001 |
3 | 1210210211212210012000120 |
4 | 13123133310002011101 |
5 | 31331112120200423 |
6 | 1030314252140453 |
7 | 51613115513601 |
oct | 7333764020521 |
9 | 1723755705016 |
10 | 510561100113 |
11 | 187589481309 |
12 | 82b49a67729 |
13 | 391b8163c3c |
14 | 1a9d5ac4c01 |
15 | d432dc7ee3 |
hex | 76dfd02151 |
510561100113 has 8 divisors (see below), whose sum is σ = 720792141408. Its totient is φ = 320352062784.
The previous prime is 510561100111. The next prime is 510561100187. The reversal of 510561100113 is 311001165015.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 510561100113 - 21 = 510561100111 is a prime.
It is a super-2 number, since 2×5105611001132 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (510561100111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5005500931 + ... + 5005501032.
It is an arithmetic number, because the mean of its divisors is an integer number (90099017676).
Almost surely, 2510561100113 is an apocalyptic number.
It is an amenable number.
510561100113 is a deficient number, since it is larger than the sum of its proper divisors (210231041295).
510561100113 is a wasteful number, since it uses less digits than its factorization.
510561100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10011001983.
The product of its (nonzero) digits is 450, while the sum is 24.
Adding to 510561100113 its reverse (311001165015), we get a palindrome (821562265128).
The spelling of 510561100113 in words is "five hundred ten billion, five hundred sixty-one million, one hundred thousand, one hundred thirteen".
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