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51084225259681 is a prime number
BaseRepresentation
bin10111001110101111110010…
…00110011010100010100001
320200212121022111021012021011
423213113321012122202201
523143430443131302211
6300351434043300521
713521466503156115
oct1347277106324241
9220777274235234
1051084225259681
111530577543a209
12589056b81a741
1322672b6304783
14c886bda19745
155d8c407b3921
hex2e75f919a8a1

51084225259681 has 2 divisors, whose sum is σ = 51084225259682. Its totient is φ = 51084225259680.

The previous prime is 51084225259667. The next prime is 51084225259687. The reversal of 51084225259681 is 18695252248015.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43872938032225 + 7211287227456 = 6623665^2 + 2685384^2 .

It is a cyclic number.

It is not a de Polignac number, because 51084225259681 - 215 = 51084225226913 is a prime.

It is a super-2 number, since 2×510842252596812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51084225259687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25542112629840 + 25542112629841.

It is an arithmetic number, because the mean of its divisors is an integer number (25542112629841).

Almost surely, 251084225259681 is an apocalyptic number.

It is an amenable number.

51084225259681 is a deficient number, since it is larger than the sum of its proper divisors (1).

51084225259681 is an equidigital number, since it uses as much as digits as its factorization.

51084225259681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824000, while the sum is 58.

The spelling of 51084225259681 in words is "fifty-one trillion, eighty-four billion, two hundred twenty-five million, two hundred fifty-nine thousand, six hundred eighty-one".