Base | Representation |
---|---|
bin | 100101001011100010001… |
… | …0101011010000011111111 |
3 | 200002111211101110020221221 |
4 | 1022113010111122003333 |
5 | 1132210300033423210 |
6 | 14511301201534211 |
7 | 1035120545565124 |
oct | 112270425320377 |
9 | 20074741406857 |
10 | 5110010061055 |
11 | 16a0163509699 |
12 | 6a6430044367 |
13 | 2b0b446a4753 |
14 | 13947c02874b |
15 | 8cdca6551da |
hex | 4a5c455a0ff |
5110010061055 has 4 divisors (see below), whose sum is σ = 6132012073272. Its totient is φ = 4088008048840.
The previous prime is 5110010061049. The next prime is 5110010061119. The reversal of 5110010061055 is 5501600100115.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5110010061055 - 219 = 5110009536767 is a prime.
It is a super-2 number, since 2×51100100610552 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511001006101 + ... + 511001006110.
It is an arithmetic number, because the mean of its divisors is an integer number (1533003018318).
Almost surely, 25110010061055 is an apocalyptic number.
5110010061055 is a deficient number, since it is larger than the sum of its proper divisors (1022002012217).
5110010061055 is a wasteful number, since it uses less digits than its factorization.
5110010061055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022002012216.
The product of its (nonzero) digits is 750, while the sum is 25.
The spelling of 5110010061055 in words is "five trillion, one hundred ten billion, ten million, sixty-one thousand, fifty-five".
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