Base | Representation |
---|---|
bin | 101111100101110011… |
… | …111101110100100011 |
3 | 11212220021010102102011 |
4 | 233211303331310203 |
5 | 1314123130322113 |
6 | 35250343333351 |
7 | 3456211626643 |
oct | 574563756443 |
9 | 155807112364 |
10 | 51100245283 |
11 | 1a74283567a |
12 | 9aa1451257 |
13 | 4a849a8239 |
14 | 268a8d4523 |
15 | 14e127863d |
hex | be5cfdd23 |
51100245283 has 2 divisors, whose sum is σ = 51100245284. Its totient is φ = 51100245282.
The previous prime is 51100245221. The next prime is 51100245337. The reversal of 51100245283 is 38254200115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51100245283 - 29 = 51100244771 is a prime.
It is a super-2 number, since 2×511002452832 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51100245083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550122641 + 25550122642.
It is an arithmetic number, because the mean of its divisors is an integer number (25550122642).
Almost surely, 251100245283 is an apocalyptic number.
51100245283 is a deficient number, since it is larger than the sum of its proper divisors (1).
51100245283 is an equidigital number, since it uses as much as digits as its factorization.
51100245283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 51100245283 its reverse (38254200115), we get a palindrome (89354445398).
The spelling of 51100245283 in words is "fifty-one billion, one hundred million, two hundred forty-five thousand, two hundred eighty-three".
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