Base | Representation |
---|---|
bin | 101111100101110011… |
… | …111111110100000011 |
3 | 11212220021010211121101 |
4 | 233211303333310003 |
5 | 1314123131102233 |
6 | 35250343435231 |
7 | 3456211662511 |
oct | 574563776403 |
9 | 155807124541 |
10 | 51100253443 |
11 | 1a742840818 |
12 | 9aa1455b17 |
13 | 4a849abb75 |
14 | 268a8d74b1 |
15 | 14e127ac7d |
hex | be5cffd03 |
51100253443 has 2 divisors, whose sum is σ = 51100253444. Its totient is φ = 51100253442.
The previous prime is 51100253411. The next prime is 51100253461. The reversal of 51100253443 is 34435200115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51100253443 - 25 = 51100253411 is a prime.
It is a super-2 number, since 2×511002534432 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51100253543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550126721 + 25550126722.
It is an arithmetic number, because the mean of its divisors is an integer number (25550126722).
Almost surely, 251100253443 is an apocalyptic number.
51100253443 is a deficient number, since it is larger than the sum of its proper divisors (1).
51100253443 is an equidigital number, since it uses as much as digits as its factorization.
51100253443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 51100253443 its reverse (34435200115), we get a palindrome (85535453558).
The spelling of 51100253443 in words is "fifty-one billion, one hundred million, two hundred fifty-three thousand, four hundred forty-three".
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