Base | Representation |
---|---|
bin | 100101001011100011101… |
… | …1100010011100111010100 |
3 | 200002111222000120020221010 |
4 | 1022113013130103213110 |
5 | 1132210401410420200 |
6 | 14511310303252220 |
7 | 1035122051015400 |
oct | 112270734234724 |
9 | 20074860506833 |
10 | 5110062201300 |
11 | 16a018a991401 |
12 | 6a64455aa070 |
13 | 2b0b5242c074 |
14 | 139484d1c100 |
15 | 8cdd0004150 |
hex | 4a5c77139d4 |
5110062201300 has 216 divisors, whose sum is σ = 17217333332640. Its totient is φ = 1166769811200.
The previous prime is 5110062201269. The next prime is 5110062201323. The reversal of 5110062201300 is 31022600115.
It is a super-3 number, since 3×51100622013003 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 13647991 + ... + 14017409.
It is an arithmetic number, because the mean of its divisors is an integer number (79709876540).
Almost surely, 25110062201300 is an apocalyptic number.
5110062201300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5110062201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (8608666666320).
5110062201300 is an abundant number, since it is smaller than the sum of its proper divisors (12107271131340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5110062201300 is a wasteful number, since it uses less digits than its factorization.
5110062201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370391 (or 370377 counting only the distinct ones).
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 5110062201300 its reverse (31022600115), we get a palindrome (5141084801415).
The spelling of 5110062201300 in words is "five trillion, one hundred ten billion, sixty-two million, two hundred one thousand, three hundred".
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