511010034343 has 4 divisors (see below), whose sum is σ = 528631070040. Its totient is φ = 493388998648.

The previous prime is 511010034299. The next prime is 511010034349. The reversal of 511010034343 is 343430010115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 511010034343 - 2³³ = 502420099751 is a prime.

It is a super-2 number, since 2×511010034343² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511010034349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8810517805 + ... + 8810517862.

It is an arithmetic number, because the mean of its divisors is an integer number (132157767510).

Almost surely, 2^511010034343 is an apocalyptic number.

511010034343 is a deficient number, since it is larger than the sum of its proper divisors (17621035697).

511010034343 is a wasteful number, since it uses less digits than its factorization.

511010034343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17621035696.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 511010034343 its reverse (343430010115), we get a palindrome (854440044458).

The spelling of 511010034343 in words is "five hundred eleven billion, ten million, thirty-four thousand, three hundred forty-three".