Base | Representation |
---|---|
bin | 111010000110001100001110… |
… | …1111001000111100100010110 |
3 | 2111000101110001010120202002020 |
4 | 1310030120131321013210112 |
5 | 1013440110231340401032 |
6 | 5010505153405354010 |
7 | 212432200356534222 |
oct | 16414303571074426 |
9 | 2430343033522066 |
10 | 511024300325142 |
11 | 13891220918071a |
12 | 49393b24268906 |
13 | 18c1b500396b56 |
14 | 90299cb087782 |
15 | 3e12dac61db2c |
hex | 1d0c61de47916 |
511024300325142 has 16 divisors (see below), whose sum is σ = 1022052128302272. Its totient is φ = 170340845499720.
The previous prime is 511024300325131. The next prime is 511024300325167. The reversal of 511024300325142 is 241523003420115.
It is a super-2 number, since 2×5110243003251422 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145100428 + ... + 148580559.
It is an arithmetic number, because the mean of its divisors is an integer number (63878258018892).
Almost surely, 2511024300325142 is an apocalyptic number.
511024300325142 is an abundant number, since it is smaller than the sum of its proper divisors (511027827977130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
511024300325142 is a wasteful number, since it uses less digits than its factorization.
511024300325142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293971003.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 511024300325142 its reverse (241523003420115), we get a palindrome (752547303745257).
The spelling of 511024300325142 in words is "five hundred eleven trillion, twenty-four billion, three hundred million, three hundred twenty-five thousand, one hundred forty-two".
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