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51103142513 is a prime number
BaseRepresentation
bin101111100101111111…
…000001001001110001
311212220110120121122222
4233211333001021301
51314124401030023
635250525410425
73456245354453
oct574577011161
9155813517588
1051103142513
111a744434385
129aa2409a15
134a85480b87
14268b04a2d3
1514e164bcc8
hexbe5fc1271

51103142513 has 2 divisors, whose sum is σ = 51103142514. Its totient is φ = 51103142512.

The previous prime is 51103142507. The next prime is 51103142527. The reversal of 51103142513 is 31524130115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50980220944 + 122921569 = 225788^2 + 11087^2 .

It is a cyclic number.

It is not a de Polignac number, because 51103142513 - 216 = 51103076977 is a prime.

It is a super-2 number, since 2×511031425132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51103142593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25551571256 + 25551571257.

It is an arithmetic number, because the mean of its divisors is an integer number (25551571257).

Almost surely, 251103142513 is an apocalyptic number.

It is an amenable number.

51103142513 is a deficient number, since it is larger than the sum of its proper divisors (1).

51103142513 is an equidigital number, since it uses as much as digits as its factorization.

51103142513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 51103142513 its reverse (31524130115), we get a palindrome (82627272628).

The spelling of 51103142513 in words is "fifty-one billion, one hundred three million, one hundred forty-two thousand, five hundred thirteen".