Base | Representation |
---|---|
bin | 100101001011101011100… |
… | …0111111111101000110111 |
3 | 200002112122100122200000220 |
4 | 1022113113013333220313 |
5 | 1132211421234441210 |
6 | 14511352342505423 |
7 | 1035131424304215 |
oct | 112272707775067 |
9 | 20075570580026 |
10 | 5110325312055 |
11 | 16a030545a407 |
12 | 6a64b9735273 |
13 | 2b0b94ab21c2 |
14 | 1394abc4bcb5 |
15 | 8cde8177c70 |
hex | 4a5d71ffa37 |
5110325312055 has 16 divisors (see below), whose sum is σ = 8179574923104. Its totient is φ = 2724488691840.
The previous prime is 5110325312041. The next prime is 5110325312087. The reversal of 5110325312055 is 5502135230115.
It is a happy number.
It is not a de Polignac number, because 5110325312055 - 25 = 5110325312023 is a prime.
It is a super-2 number, since 2×51103253120552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63592336 + ... + 63672645.
It is an arithmetic number, because the mean of its divisors is an integer number (511223432694).
Almost surely, 25110325312055 is an apocalyptic number.
5110325312055 is a deficient number, since it is larger than the sum of its proper divisors (3069249611049).
5110325312055 is a wasteful number, since it uses less digits than its factorization.
5110325312055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127267666.
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 5110325312055 in words is "five trillion, one hundred ten billion, three hundred twenty-five million, three hundred twelve thousand, fifty-five".
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