Base | Representation |
---|---|
bin | 100101001011101011100… |
… | …1000000010000110101001 |
3 | 200002112122100200011212220 |
4 | 1022113113020002012221 |
5 | 1132211421240302103 |
6 | 14511352343024253 |
7 | 1035131424345522 |
oct | 112272710020651 |
9 | 20075570604786 |
10 | 5110325322153 |
11 | 16a0305466a57 |
12 | 6a64b973b089 |
13 | 2b0b94ab698c |
14 | 1394abc51849 |
15 | 8cde817ac53 |
hex | 4a5d72021a9 |
5110325322153 has 32 divisors (see below), whose sum is σ = 7108464528000. Its totient is φ = 3261568128000.
The previous prime is 5110325322097. The next prime is 5110325322173. The reversal of 5110325322153 is 3512235230115.
It is not a de Polignac number, because 5110325322153 - 212 = 5110325318057 is a prime.
It is a super-2 number, since 2×51103253221532 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5110325322173) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13501123 + ... + 13874471.
It is an arithmetic number, because the mean of its divisors is an integer number (222139516500).
Almost surely, 25110325322153 is an apocalyptic number.
It is an amenable number.
5110325322153 is a deficient number, since it is larger than the sum of its proper divisors (1998139205847).
5110325322153 is a wasteful number, since it uses less digits than its factorization.
5110325322153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 374713.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 5110325322153 in words is "five trillion, one hundred ten billion, three hundred twenty-five million, three hundred twenty-two thousand, one hundred fifty-three".
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