Base | Representation |
---|---|
bin | 101111100110000011… |
… | …100111111110000001 |
3 | 11212220112211222010201 |
4 | 233212003213332001 |
5 | 1314130203200311 |
6 | 35251011325201 |
7 | 3456261544201 |
oct | 574603477601 |
9 | 155815758121 |
10 | 51104350081 |
11 | 1a745089674 |
12 | 9aa28b0801 |
13 | 4a857b4705 |
14 | 268b282401 |
15 | 14e17d99c1 |
hex | be60e7f81 |
51104350081 has 2 divisors, whose sum is σ = 51104350082. Its totient is φ = 51104350080.
The previous prime is 51104350057. The next prime is 51104350111. The reversal of 51104350081 is 18005340115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42815886400 + 8288463681 = 206920^2 + 91041^2 .
It is a cyclic number.
It is not a de Polignac number, because 51104350081 - 27 = 51104349953 is a prime.
It is a super-2 number, since 2×511043500812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51104350181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25552175040 + 25552175041.
It is an arithmetic number, because the mean of its divisors is an integer number (25552175041).
Almost surely, 251104350081 is an apocalyptic number.
It is an amenable number.
51104350081 is a deficient number, since it is larger than the sum of its proper divisors (1).
51104350081 is an equidigital number, since it uses as much as digits as its factorization.
51104350081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 51104350081 its reverse (18005340115), we get a palindrome (69109690196).
The spelling of 51104350081 in words is "fifty-one billion, one hundred four million, three hundred fifty thousand, eighty-one".
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