Base | Representation |
---|---|
bin | 1001100001001101… |
… | …10101011011101001 |
3 | 111012011012221221211 |
4 | 10300212311123221 |
5 | 40431234011433 |
6 | 2203034433121 |
7 | 240433066531 |
oct | 46046653351 |
9 | 14164187854 |
10 | 5110453993 |
11 | 21927997a7 |
12 | ba75927a1 |
13 | 6359c2798 |
14 | 366a144c1 |
15 | 1ed9c38cd |
hex | 1309b56e9 |
5110453993 has 2 divisors, whose sum is σ = 5110453994. Its totient is φ = 5110453992.
The previous prime is 5110453967. The next prime is 5110454003. The reversal of 5110453993 is 3993540115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3081582144 + 2028871849 = 55512^2 + 45043^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5110453993 is a prime.
It is a super-2 number, since 2×51104539932 = 52233480029139288098, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110453393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555226996 + 2555226997.
It is an arithmetic number, because the mean of its divisors is an integer number (2555226997).
Almost surely, 25110453993 is an apocalyptic number.
It is an amenable number.
5110453993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110453993 is an equidigital number, since it uses as much as digits as its factorization.
5110453993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72900, while the sum is 40.
The square root of 5110453993 is about 71487.4394072133. The cubic root of 5110453993 is about 1722.4759268432.
The spelling of 5110453993 in words is "five billion, one hundred ten million, four hundred fifty-three thousand, nine hundred ninety-three".
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