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51105112041 = 3195330755103
BaseRepresentation
bin101111100110000110…
…100001111111101001
311212220121021200100110
4233212012201333221
51314130402041131
635251035524533
73456301166514
oct574606417751
9155817250313
1051105112041
111a74555a095
129aa2bb9749
134a859c0489
14268b3ddd7b
1514e18da646
hexbe61a1fe9

51105112041 has 32 divisors (see below), whose sum is σ = 73319178240. Its totient is φ = 31564188864.

The previous prime is 51105112033. The next prime is 51105112043. The reversal of 51105112041 is 14021150115.

It is not a de Polignac number, because 51105112041 - 23 = 51105112033 is a prime.

It is a super-2 number, since 2×511051120412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51105111999 and 51105112017.

It is not an unprimeable number, because it can be changed into a prime (51105112043) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 899896 + ... + 954998.

It is an arithmetic number, because the mean of its divisors is an integer number (2291224320).

Almost surely, 251105112041 is an apocalyptic number.

It is an amenable number.

51105112041 is a deficient number, since it is larger than the sum of its proper divisors (22214066199).

51105112041 is a wasteful number, since it uses less digits than its factorization.

51105112041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55485.

The product of its (nonzero) digits is 200, while the sum is 21.

Adding to 51105112041 its reverse (14021150115), we get a palindrome (65126262156).

The spelling of 51105112041 in words is "fifty-one billion, one hundred five million, one hundred twelve thousand, forty-one".

Divisors: 1 3 19 53 57 159 307 921 1007 3021 5833 16271 17499 48813 55103 165309 309149 927447 1046957 2920459 3140871 8761377 16916621 50749863 55488721 166466163 321415799 896580913 964247397 2689742739 17035037347 51105112041