Base | Representation |
---|---|
bin | 100101001011110011110… |
… | …0000001110101010100001 |
3 | 200002120100111201100221012 |
4 | 1022113213200032222201 |
5 | 1132213002111204023 |
6 | 14511435520310305 |
7 | 1035141302050565 |
oct | 112274740165241 |
9 | 20076314640835 |
10 | 5110600100513 |
11 | 16a0436584006 |
12 | 6a6575772395 |
13 | 2b0c099c371b |
14 | 1394d653b6a5 |
15 | 8ce12356978 |
hex | 4a5e780eaa1 |
5110600100513 has 2 divisors, whose sum is σ = 5110600100514. Its totient is φ = 5110600100512.
The previous prime is 5110600100371. The next prime is 5110600100519. The reversal of 5110600100513 is 3150010060115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2857289883904 + 2253310216609 = 1690352^2 + 1501103^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110600100513 - 218 = 5110599838369 is a prime.
It is a super-2 number, since 2×51106001005132 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5110600100519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555300050256 + 2555300050257.
It is an arithmetic number, because the mean of its divisors is an integer number (2555300050257).
Almost surely, 25110600100513 is an apocalyptic number.
It is an amenable number.
5110600100513 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110600100513 is an equidigital number, since it uses as much as digits as its factorization.
5110600100513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 5110600100513 its reverse (3150010060115), we get a palindrome (8260610160628).
The spelling of 5110600100513 in words is "five trillion, one hundred ten billion, six hundred million, one hundred thousand, five hundred thirteen".
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