Base | Representation |
---|---|
bin | 100101001011110110110… |
… | …0001101011010100011001 |
3 | 200002120121112211212121102 |
4 | 1022113231201223110121 |
5 | 1132213203443041241 |
6 | 14511453530121145 |
7 | 1035143636645204 |
oct | 112275541532431 |
9 | 20076545755542 |
10 | 5110701143321 |
11 | 16a0488617a64 |
12 | 6a65a35801b5 |
13 | 2b0c24910a77 |
14 | 139505b2093b |
15 | 8ce1b16539b |
hex | 4a5ed86b519 |
5110701143321 has 2 divisors, whose sum is σ = 5110701143322. Its totient is φ = 5110701143320.
The previous prime is 5110701143297. The next prime is 5110701143347. The reversal of 5110701143321 is 1233411070115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5110149598096 + 551545225 = 2260564^2 + 23485^2 .
It is a cyclic number.
It is not a de Polignac number, because 5110701143321 - 26 = 5110701143257 is a prime.
It is a super-3 number, since 3×51107011433213 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (5110701143371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555350571660 + 2555350571661.
It is an arithmetic number, because the mean of its divisors is an integer number (2555350571661).
Almost surely, 25110701143321 is an apocalyptic number.
It is an amenable number.
5110701143321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5110701143321 is an equidigital number, since it uses as much as digits as its factorization.
5110701143321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 29.
The spelling of 5110701143321 in words is "five trillion, one hundred ten billion, seven hundred one million, one hundred forty-three thousand, three hundred twenty-one".
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