51107113 has 2 divisors, whose sum is σ = 51107114. Its totient is φ = 51107112.

The previous prime is 51107107. The next prime is 51107123. The reversal of 51107113 is 31170115.

51107113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49674304 + 1432809 = 7048^2 + 1197^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51107113 is a prime.

It is a super-2 number, since 2×51107113² = 5223873998389538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (51107123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25553556 + 25553557.

It is an arithmetic number, because the mean of its divisors is an integer number (25553557).

Almost surely, 2^51107113 is an apocalyptic number.

It is an amenable number.

51107113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51107113 is an equidigital number, since it uses as much as digits as its factorization.

51107113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 105, while the sum is 19.

The square root of 51107113 is about 7148.9239050363. The cubic root of 51107113 is about 371.1024169746.

Adding to 51107113 its reverse (31170115), we get a palindrome (82277228).

The spelling of 51107113 in words is "fifty-one million, one hundred seven thousand, one hundred thirteen".