51111414040133 has 4 divisors (see below), whose sum is σ = 51115559677740. Its totient is φ = 51107268402528.

The previous prime is 51111414040111. The next prime is 51111414040171. The reversal of 51111414040133 is 33104041411115.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 528053648929 + 50583360391204 = 726673^2 + 7112198^2 .

It is a cyclic number.

It is not a de Polignac number, because 51111414040133 - 2¹⁸ = 51111413777989 is a prime.

It is a super-2 number, since 2×51111414040133² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51111414040096 and 51111414040105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51111414040033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2072800310 + ... + 2072824967.

It is an arithmetic number, because the mean of its divisors is an integer number (12778889919435).

Almost surely, 2^{51111414040133} is an apocalyptic number.

It is an amenable number.

51111414040133 is a deficient number, since it is larger than the sum of its proper divisors (4145637607).

51111414040133 is a wasteful number, since it uses less digits than its factorization.

51111414040133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4145637606.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 51111414040133 its reverse (33104041411115), we get a palindrome (84215455451248).

The spelling of 51111414040133 in words is "fifty-one trillion, one hundred eleven billion, four hundred fourteen million, forty thousand, one hundred thirty-three".