Base | Representation |
---|---|
bin | 100101001100000011111… |
… | …0111101100100010111111 |
3 | 200002121202100111202221011 |
4 | 1022120013313230202333 |
5 | 1132220110114420020 |
6 | 14512005435220051 |
7 | 1035160614502120 |
oct | 112300767544277 |
9 | 20077670452834 |
10 | 5111143123135 |
11 | 16a0695055a35 |
12 | 6a66a75a7627 |
13 | 2b0c9536009a |
14 | 1395486d2047 |
15 | 8ce44d6c35a |
hex | 4a607dec8bf |
5111143123135 has 16 divisors (see below), whose sum is σ = 7009665062400. Its totient is φ = 3504735180576.
The previous prime is 5111143123129. The next prime is 5111143123183. The reversal of 5111143123135 is 5313213411115.
It is a happy number.
5111143123135 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5111143123135 - 241 = 2912119867583 is a prime.
It is a super-2 number, since 2×51111431231352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111143123097 and 5111143123106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1639876 + ... + 3593254.
It is an arithmetic number, because the mean of its divisors is an integer number (438104066400).
Almost surely, 25111143123135 is an apocalyptic number.
5111143123135 is a deficient number, since it is larger than the sum of its proper divisors (1898521939265).
5111143123135 is a wasteful number, since it uses less digits than its factorization.
5111143123135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2028150.
The product of its digits is 5400, while the sum is 31.
The spelling of 5111143123135 in words is "five trillion, one hundred eleven billion, one hundred forty-three million, one hundred twenty-three thousand, one hundred thirty-five".
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