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5111224147 is a prime number
BaseRepresentation
bin1001100001010011…
…10001011101010011
3111012012200002102001
410300221301131103
540431433133042
62203103134431
7240442455061
oct46051613523
914165602361
105111224147
112193175397
12ba78a4417
13635c021b3
14366b75031
151edac6bb7
hex130a71753

5111224147 has 2 divisors, whose sum is σ = 5111224148. Its totient is φ = 5111224146.

The previous prime is 5111224091. The next prime is 5111224163. The reversal of 5111224147 is 7414221115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5111224147 - 219 = 5110699859 is a prime.

It is a super-2 number, since 2×51112241472 = 52249224561751755218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5111224187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555612073 + 2555612074.

It is an arithmetic number, because the mean of its divisors is an integer number (2555612074).

Almost surely, 25111224147 is an apocalyptic number.

5111224147 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111224147 is an equidigital number, since it uses as much as digits as its factorization.

5111224147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2240, while the sum is 28.

The square root of 5111224147 is about 71492.8258428774. The cubic root of 5111224147 is about 1722.5624491688.

The spelling of 5111224147 in words is "five billion, one hundred eleven million, two hundred twenty-four thousand, one hundred forty-seven".