Base | Representation |
---|---|
bin | 100101001100000111000… |
… | …1111011100010100111111 |
3 | 200002122000210122021010211 |
4 | 1022120032033130110333 |
5 | 1132220320000331310 |
6 | 14512024214213251 |
7 | 1035163353153640 |
oct | 112301617342477 |
9 | 20078023567124 |
10 | 5111250011455 |
11 | 16a073a421795 |
12 | 6a6717354227 |
13 | 2b0cb1546003 |
14 | 1395589976c7 |
15 | 8ce4e432c8a |
hex | 4a60e3dc53f |
5111250011455 has 32 divisors (see below), whose sum is σ = 7264173571200. Its totient is φ = 3378052349952.
The previous prime is 5111250011431. The next prime is 5111250011501. The reversal of 5111250011455 is 5541100521115.
It is not a de Polignac number, because 5111250011455 - 25 = 5111250011423 is a prime.
It is a super-2 number, since 2×51112500114552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3847522 + ... + 5002591.
It is an arithmetic number, because the mean of its divisors is an integer number (227005424100).
Almost surely, 25111250011455 is an apocalyptic number.
5111250011455 is a deficient number, since it is larger than the sum of its proper divisors (2152923559745).
5111250011455 is a wasteful number, since it uses less digits than its factorization.
5111250011455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8850723.
The product of its (nonzero) digits is 5000, while the sum is 31.
The spelling of 5111250011455 in words is "five trillion, one hundred eleven billion, two hundred fifty million, eleven thousand, four hundred fifty-five".
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