5111311142137 has 2 divisors, whose sum is σ = 5111311142138. Its totient is φ = 5111311142136.

The previous prime is 5111311142131. The next prime is 5111311142141. The reversal of 5111311142137 is 7312411131115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2818037047401 + 2293274094736 = 1678701^2 + 1514356^2 .

It is a cyclic number.

It is not a de Polignac number, because 5111311142137 - 2¹⁵ = 5111311109369 is a prime.

It is a super-2 number, since 2×5111311142137² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111311142099 and 5111311142108.

It is not a weakly prime, because it can be changed into another prime (5111311142131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555655571068 + 2555655571069.

It is an arithmetic number, because the mean of its divisors is an integer number (2555655571069).

Almost surely, 2^{5111311142137} is an apocalyptic number.

It is an amenable number.

5111311142137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5111311142137 is an equidigital number, since it uses as much as digits as its factorization.

5111311142137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2520, while the sum is 31.

The spelling of 5111311142137 in words is "five trillion, one hundred eleven billion, three hundred eleven million, one hundred forty-two thousand, one hundred thirty-seven".