Base | Representation |
---|---|
bin | 101111100110100101… |
… | …010111010101011011 |
3 | 11212221011111022212111 |
4 | 233212211113111123 |
5 | 1314134434213333 |
6 | 35251525053151 |
7 | 3456426662524 |
oct | 574645272533 |
9 | 155834438774 |
10 | 51113194843 |
11 | 1a74a07a897 |
12 | 9aa58571b7 |
13 | 4a875904b9 |
14 | 268c50584b |
15 | 14e24854cd |
hex | be695755b |
51113194843 has 2 divisors, whose sum is σ = 51113194844. Its totient is φ = 51113194842.
The previous prime is 51113194799. The next prime is 51113194871. The reversal of 51113194843 is 34849131115.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51113194843 is a prime.
It is a super-2 number, since 2×511131948432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51113194796 and 51113194805.
It is not a weakly prime, because it can be changed into another prime (51113194243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25556597421 + 25556597422.
It is an arithmetic number, because the mean of its divisors is an integer number (25556597422).
Almost surely, 251113194843 is an apocalyptic number.
51113194843 is a deficient number, since it is larger than the sum of its proper divisors (1).
51113194843 is an equidigital number, since it uses as much as digits as its factorization.
51113194843 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 40.
The spelling of 51113194843 in words is "fifty-one billion, one hundred thirteen million, one hundred ninety-four thousand, eight hundred forty-three".
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