Base | Representation |
---|---|
bin | 100101001100001001001… |
… | …1010100101001001000001 |
3 | 200002122012200102002020200 |
4 | 1022120102122211021001 |
5 | 1132220440412240001 |
6 | 14512035155155413 |
7 | 1035165163326540 |
oct | 112302232451101 |
9 | 20078180362220 |
10 | 5111320040001 |
11 | 16a0775a0221a |
12 | 6a67368a5b69 |
13 | 2b0cc2bc4816 |
14 | 139563dc6157 |
15 | 8ce55667086 |
hex | 4a6126a5241 |
5111320040001 has 48 divisors (see below), whose sum is σ = 9009350777856. Its totient is φ = 2728793678688.
The previous prime is 5111320039993. The next prime is 5111320040027. The reversal of 5111320040001 is 1000400231115.
5111320040001 is a `hidden beast` number, since 51 + 1 + 13 + 200 + 400 + 0 + 1 = 666.
It is not a de Polignac number, because 5111320040001 - 23 = 5111320039993 is a prime.
It is a super-2 number, since 2×51113200400012 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5111320030001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 40954915 + ... + 41079528.
It is an arithmetic number, because the mean of its divisors is an integer number (187694807872).
Almost surely, 25111320040001 is an apocalyptic number.
It is an amenable number.
5111320040001 is a deficient number, since it is larger than the sum of its proper divisors (3898030737855).
5111320040001 is a wasteful number, since it uses less digits than its factorization.
5111320040001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82034522 (or 82034519 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
Adding to 5111320040001 its reverse (1000400231115), we get a palindrome (6111720271116).
The spelling of 5111320040001 in words is "five trillion, one hundred eleven billion, three hundred twenty million, forty thousand, one".
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