Base | Representation |
---|---|
bin | 100101001100001001110… |
… | …0111001111001110110001 |
3 | 200002122021002020000212200 |
4 | 1022120103213033032301 |
5 | 1132221011033312340 |
6 | 14512041154013413 |
7 | 1035165526203543 |
oct | 112302347171661 |
9 | 20078232200780 |
10 | 5111340135345 |
11 | 16a0786288144 |
12 | 6a6741577269 |
13 | 2b0cc710c462 |
14 | 139566937693 |
15 | 8ce572d6330 |
hex | 4a6139cf3b1 |
5111340135345 has 48 divisors (see below), whose sum is σ = 9381381939072. Its totient is φ = 2565536555520.
The previous prime is 5111340135287. The next prime is 5111340135403. The reversal of 5111340135345 is 5435310431115.
5111340135345 is a `hidden beast` number, since 5 + 1 + 113 + 4 + 0 + 1 + 3 + 534 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (5111340135287) and next prime (5111340135403).
It is not a de Polignac number, because 5111340135345 - 27 = 5111340135217 is a prime.
It is a super-2 number, since 2×51113401353452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12966100 + ... + 13354490.
It is an arithmetic number, because the mean of its divisors is an integer number (195445457064).
Almost surely, 25111340135345 is an apocalyptic number.
It is an amenable number.
5111340135345 is a deficient number, since it is larger than the sum of its proper divisors (4270041803727).
5111340135345 is a wasteful number, since it uses less digits than its factorization.
5111340135345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 405622 (or 405619 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
The spelling of 5111340135345 in words is "five trillion, one hundred eleven billion, three hundred forty million, one hundred thirty-five thousand, three hundred forty-five".
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