Base | Representation |
---|---|
bin | 101111100110100110… |
… | …010001000001001011 |
3 | 11212221011221022222022 |
4 | 233212212101001023 |
5 | 1314140014243430 |
6 | 35251534115055 |
7 | 3456431665415 |
oct | 574646210113 |
9 | 155834838868 |
10 | 51113431115 |
11 | 1a74a22135a |
12 | 9aa594ba8b |
13 | 4a87643bc6 |
14 | 268c5679b5 |
15 | 14e24d04e5 |
hex | be699104b |
51113431115 has 8 divisors (see below), whose sum is σ = 64564334160. Its totient is φ = 38738600352.
The previous prime is 51113431099. The next prime is 51113431121.
51113431115 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51113431115 - 24 = 51113431099 is a prime.
It is a super-2 number, since 2×511134311152 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269017964 + ... + 269018153.
It is an arithmetic number, because the mean of its divisors is an integer number (8070541770).
Almost surely, 251113431115 is an apocalyptic number.
51113431115 is a deficient number, since it is larger than the sum of its proper divisors (13450903045).
51113431115 is a wasteful number, since it uses less digits than its factorization.
51113431115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 538036141.
The product of its digits is 900, while the sum is 26.
The spelling of 51113431115 in words is "fifty-one billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred fifteen".
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